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13353111400153 = 713019914651321
BaseRepresentation
bin1100001001010000001101…
…1101100010111011011001
31202021112201021220020021011
43002110003131202323121
53222234133004301103
644222200143213521
72545505356105210
oct302240335427331
952245637806234
1013353111400153
1142890282a8028
1215b7b09ba72a1
1375b268043a05
14342418bbc077
15182529936d6d
hexc2503762ed9

13353111400153 has 8 divisors (see below), whose sum is σ = 15260816995200. Its totient is φ = 11445435368160.

The previous prime is 13353111400127. The next prime is 13353111400219. The reversal of 13353111400153 is 35100411135331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13353111400153 - 217 = 13353111269081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13353111400253) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6414268 + ... + 8237053.

It is an arithmetic number, because the mean of its divisors is an integer number (1907602124400).

Almost surely, 213353111400153 is an apocalyptic number.

It is an amenable number.

13353111400153 is a deficient number, since it is larger than the sum of its proper divisors (1907705595047).

13353111400153 is a wasteful number, since it uses less digits than its factorization.

13353111400153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14781527.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 13353111400153 its reverse (35100411135331), we get a palindrome (48453522535484).

The spelling of 13353111400153 in words is "thirteen trillion, three hundred fifty-three billion, one hundred eleven million, four hundred thousand, one hundred fifty-three".

Divisors: 1 7 130199 911393 14651321 102559247 1907587342879 13353111400153