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13353443450212 = 223338360862553
BaseRepresentation
bin1100001001010001011101…
…0000001101110101100100
31202021120120102201010022111
43002110113100031311210
53222240323010401322
644222253124210404
72545516530352165
oct302242720156544
952246512633274
1013353443450212
114289188782168
1215b7ba1239a04
1375b2bba83938
1434244ad3576c
15182548b77177
hexc251740dd64

13353443450212 has 6 divisors (see below), whose sum is σ = 23368526037878. Its totient is φ = 6676721725104.

The previous prime is 13353443450143. The next prime is 13353443450219. The reversal of 13353443450212 is 21205434435331.

It can be written as a sum of positive squares in only one way, i.e., 13336110674496 + 17332775716 = 3651864^2 + 131654^2 .

It is a super-3 number, since 3×133534434502123 (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (13353443450219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1669180431273 + ... + 1669180431280.

Almost surely, 213353443450212 is an apocalyptic number.

It is an amenable number.

13353443450212 is a deficient number, since it is larger than the sum of its proper divisors (10015082587666).

13353443450212 is a wasteful number, since it uses less digits than its factorization.

13353443450212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3338360862557 (or 3338360862555 counting only the distinct ones).

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 13353443450212 its reverse (21205434435331), we get a palindrome (34558877885543).

The spelling of 13353443450212 in words is "thirteen trillion, three hundred fifty-three billion, four hundred forty-three million, four hundred fifty thousand, two hundred twelve".

Divisors: 1 2 4 3338360862553 6676721725106 13353443450212