Base | Representation |
---|---|
bin | 1100001001010001011110… |
… | …1110111011011001011001 |
3 | 1202021120120222212011010012 |
4 | 3002110113232323121121 |
5 | 3222240332041014040 |
6 | 44222254012531305 |
7 | 2545516655653250 |
oct | 302242756733131 |
9 | 52246528764105 |
10 | 13353451501145 |
11 | 4289192280a28 |
12 | 15b7ba3a80b35 |
13 | 75b2c06422c2 |
14 | 34244c02d797 |
15 | 182549717865 |
hex | c2517bbb659 |
13353451501145 has 32 divisors (see below), whose sum is σ = 18373172882688. Its totient is φ = 9126725084928.
The previous prime is 13353451501139. The next prime is 13353451501163. The reversal of 13353451501145 is 54110515435331.
It is a cyclic number.
It is not a de Polignac number, because 13353451501145 - 210 = 13353451500121 is a prime.
It is a super-2 number, since 2×133534515011452 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 104262287 + ... + 104390283.
It is an arithmetic number, because the mean of its divisors is an integer number (574161652584).
Almost surely, 213353451501145 is an apocalyptic number.
It is an amenable number.
13353451501145 is a deficient number, since it is larger than the sum of its proper divisors (5019721381543).
13353451501145 is a wasteful number, since it uses less digits than its factorization.
13353451501145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137729.
The product of its (nonzero) digits is 270000, while the sum is 41.
Adding to 13353451501145 its reverse (54110515435331), we get a palindrome (67463966936476).
The spelling of 13353451501145 in words is "thirteen trillion, three hundred fifty-three billion, four hundred fifty-one million, five hundred one thousand, one hundred forty-five".
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