Base | Representation |
---|---|
bin | 11110010111001100001010… |
… | …010001011010000100100011 |
3 | 122111210211011210011200201211 |
4 | 132113030022101122010203 |
5 | 120000314140114112311 |
6 | 1152001044331410551 |
7 | 40061404540401253 |
oct | 3627141221320443 |
9 | 574724153150654 |
10 | 133535000535331 |
11 | 3960396a60865a |
12 | 12b87b895b3a57 |
13 | 59683b15b3395 |
14 | 24d91b28c3963 |
15 | 1068842559821 |
hex | 79730a45a123 |
133535000535331 has 4 divisors (see below), whose sum is σ = 134831456851312. Its totient is φ = 132238544219352.
The previous prime is 133535000535283. The next prime is 133535000535337.
133535000535331 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133535000535331 - 217 = 133535000404259 is a prime.
It is a super-2 number, since 2×1335350005353312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133535000535337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 648228157836 + ... + 648228158041.
It is an arithmetic number, because the mean of its divisors is an integer number (33707864212828).
Almost surely, 2133535000535331 is an apocalyptic number.
133535000535331 is a deficient number, since it is larger than the sum of its proper divisors (1296456315981).
133535000535331 is a wasteful number, since it uses less digits than its factorization.
133535000535331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1296456315980.
The product of its (nonzero) digits is 455625, while the sum is 40.
The spelling of 133535000535331 in words is "one hundred thirty-three trillion, five hundred thirty-five billion, five hundred thirty-five thousand, three hundred thirty-one".
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