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13353521111257 is a prime number
BaseRepresentation
bin1100001001010001101111…
…1000011110000011011001
31202021120202211211201020111
43002110123320132003121
53222241002401030012
644222304540524321
72545521462434215
oct302243370360331
952246684751214
1013353521111257
1142892185a6048
1215b80032506a1
1375b301ba5512
1434245738d945
151825508b7ba7
hexc251be1e0d9

13353521111257 has 2 divisors, whose sum is σ = 13353521111258. Its totient is φ = 13353521111256.

The previous prime is 13353521111143. The next prime is 13353521111299. The reversal of 13353521111257 is 75211112535331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12803400737856 + 550120373401 = 3578184^2 + 741701^2 .

It is a cyclic number.

It is not a de Polignac number, because 13353521111257 - 27 = 13353521111129 is a prime.

It is not a weakly prime, because it can be changed into another prime (13353527111257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676760555628 + 6676760555629.

It is an arithmetic number, because the mean of its divisors is an integer number (6676760555629).

Almost surely, 213353521111257 is an apocalyptic number.

It is an amenable number.

13353521111257 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353521111257 is an equidigital number, since it uses as much as digits as its factorization.

13353521111257 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 94500, while the sum is 40.

Adding to 13353521111257 its reverse (75211112535331), we get a palindrome (88564633646588).

The spelling of 13353521111257 in words is "thirteen trillion, three hundred fifty-three billion, five hundred twenty-one million, one hundred eleven thousand, two hundred fifty-seven".