Base | Representation |
---|---|
bin | 1100001001010001110000… |
… | …0000111001010011000001 |
3 | 1202021120202222222221001211 |
4 | 3002110130000321103001 |
5 | 3222241003432220001 |
6 | 44222305100130121 |
7 | 2545521520263544 |
oct | 302243400712301 |
9 | 52246688887054 |
10 | 13353523320001 |
11 | 4289219874557 |
12 | 15b8003b36941 |
13 | 75b302499977 |
14 | 3424577a685b |
15 | 182550ba2351 |
hex | c251c0394c1 |
13353523320001 has 4 divisors (see below), whose sum is σ = 13355344841904. Its totient is φ = 13351701798100.
The previous prime is 13353523319837. The next prime is 13353523320029. The reversal of 13353523320001 is 10002332535331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13353523320001 - 225 = 13353489765569 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13353523320041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 910749955 + ... + 910764616.
It is an arithmetic number, because the mean of its divisors is an integer number (3338836210476).
Almost surely, 213353523320001 is an apocalyptic number.
It is an amenable number.
13353523320001 is a deficient number, since it is larger than the sum of its proper divisors (1821521903).
13353523320001 is an equidigital number, since it uses as much as digits as its factorization.
13353523320001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1821521902.
The product of its (nonzero) digits is 24300, while the sum is 31.
Adding to 13353523320001 its reverse (10002332535331), we get a palindrome (23355855855332).
The spelling of 13353523320001 in words is "thirteen trillion, three hundred fifty-three billion, five hundred twenty-three million, three hundred twenty thousand, one".
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