Base | Representation |
---|---|
bin | 1100001001010001110010… |
… | …1010100001001010101011 |
3 | 1202021120210202112021102201 |
4 | 3002110130222201022223 |
5 | 3222241014230344321 |
6 | 44222310130041031 |
7 | 2545522012106626 |
oct | 302243452411253 |
9 | 52246722467381 |
10 | 13353534231211 |
11 | 4289224a47289 |
12 | 15b8007719177 |
13 | 75b30481a1c5 |
14 | 342459006dbd |
15 | 182551b0a291 |
hex | c251caa12ab |
13353534231211 has 2 divisors, whose sum is σ = 13353534231212. Its totient is φ = 13353534231210.
The previous prime is 13353534231179. The next prime is 13353534231227. The reversal of 13353534231211 is 11213243535331.
It is a strong prime.
It is an emirp because it is prime and its reverse (11213243535331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13353534231211 - 25 = 13353534231179 is a prime.
It is not a weakly prime, because it can be changed into another prime (13353537231211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676767115605 + 6676767115606.
It is an arithmetic number, because the mean of its divisors is an integer number (6676767115606).
Almost surely, 213353534231211 is an apocalyptic number.
13353534231211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13353534231211 is an equidigital number, since it uses as much as digits as its factorization.
13353534231211 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 97200, while the sum is 37.
Adding to 13353534231211 its reverse (11213243535331), we get a palindrome (24566777766542).
The spelling of 13353534231211 in words is "thirteen trillion, three hundred fifty-three billion, five hundred thirty-four million, two hundred thirty-one thousand, two hundred eleven".
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