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13354002403355 = 529857107463907
BaseRepresentation
bin1100001001010011100010…
…0100011101000000011011
31202021122000101110212212202
43002110320210131000123
53222242444103401410
644222424412400415
72545536425363165
oct302247044350033
952248011425782
1013354002403355
114289445244a09
1215b811847610b
1375b37a80a343
143424a1275935
1518257cc87ca5
hexc253891d01b

13354002403355 has 16 divisors (see below), whose sum is σ = 16596725951520. Its totient is φ = 10302779596032.

The previous prime is 13354002403337. The next prime is 13354002403367. The reversal of 13354002403355 is 55330420045331.

It is a cyclic number.

It is not a de Polignac number, because 13354002403355 - 218 = 13354002141211 is a prime.

It is a super-2 number, since 2×133540024033552 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53607689 + ... + 53856218.

It is an arithmetic number, because the mean of its divisors is an integer number (1037295371970).

Almost surely, 213354002403355 is an apocalyptic number.

13354002403355 is a deficient number, since it is larger than the sum of its proper divisors (3242723548165).

13354002403355 is a wasteful number, since it uses less digits than its factorization.

13354002403355 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 107464798.

The product of its (nonzero) digits is 324000, while the sum is 38.

Adding to 13354002403355 its reverse (55330420045331), we get a palindrome (68684422448686).

The spelling of 13354002403355 in words is "thirteen trillion, three hundred fifty-four billion, two million, four hundred three thousand, three hundred fifty-five".

Divisors: 1 5 29 145 857 4285 24853 124265 107463907 537319535 3116453303 15582266515 92096568299 460482841495 2670800480671 13354002403355