Base | Representation |
---|---|
bin | 1100001001010011100010… |
… | …0100100110101100000011 |
3 | 1202021122000101112220021111 |
4 | 3002110320210212230003 |
5 | 3222242444111134021 |
6 | 44222424413304151 |
7 | 2545536425616616 |
oct | 302247044465403 |
9 | 52248011486244 |
10 | 13354002443011 |
11 | 428944527178a |
12 | 15b8118495057 |
13 | 75b37a8223c9 |
14 | 3424a128617d |
15 | 18257cc948e1 |
hex | c2538926b03 |
13354002443011 has 4 divisors (see below), whose sum is σ = 13355692617024. Its totient is φ = 13352312269000.
The previous prime is 13354002443009. The next prime is 13354002443051. The reversal of 13354002443011 is 11034420045331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13354002443011 - 21 = 13354002443009 is a prime.
It is a super-2 number, since 2×133540024430112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13354002443051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 845075155 + ... + 845090956.
It is an arithmetic number, because the mean of its divisors is an integer number (3338923154256).
Almost surely, 213354002443011 is an apocalyptic number.
13354002443011 is a deficient number, since it is larger than the sum of its proper divisors (1690174013).
13354002443011 is an equidigital number, since it uses as much as digits as its factorization.
13354002443011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1690174012.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13354002443011 its reverse (11034420045331), we get a palindrome (24388422488342).
The spelling of 13354002443011 in words is "thirteen trillion, three hundred fifty-four billion, two million, four hundred forty-three thousand, eleven".
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