Base | Representation |
---|---|
bin | 100111110011000… |
… | …1001101100010001 |
3 | 10110001210102002221 |
4 | 1033212021230101 |
5 | 10213330314413 |
6 | 340302141041 |
7 | 45043503025 |
oct | 11746115421 |
9 | 3401712087 |
10 | 1335401233 |
11 | 625887791 |
12 | 313281781 |
13 | 18388155a |
14 | c94d8385 |
15 | 7c38468d |
hex | 4f989b11 |
1335401233 has 2 divisors, whose sum is σ = 1335401234. Its totient is φ = 1335401232.
The previous prime is 1335401159. The next prime is 1335401257. The reversal of 1335401233 is 3321045331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1101708864 + 233692369 = 33192^2 + 15287^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1335401233 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1335401198 and 1335401207.
It is not a weakly prime, because it can be changed into another prime (1335401533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667700616 + 667700617.
It is an arithmetic number, because the mean of its divisors is an integer number (667700617).
Almost surely, 21335401233 is an apocalyptic number.
It is an amenable number.
1335401233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1335401233 is an equidigital number, since it uses as much as digits as its factorization.
1335401233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 25.
The square root of 1335401233 is about 36543.1420789182. The cubic root of 1335401233 is about 1101.2111269118.
Adding to 1335401233 its reverse (3321045331), we get a palindrome (4656446564).
The spelling of 1335401233 in words is "one billion, three hundred thirty-five million, four hundred one thousand, two hundred thirty-three".
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