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13354450243403 = 69119326266633
BaseRepresentation
bin1100001001010101001101…
…0000110100111101001011
31202021200011121011111221012
43002111103100310331023
53222244403230242103
644222541051234135
72545553504065253
oct302252320647513
952250147144835
1013354450243403
114289655015855
1215b822244894b
1375b41c52bb59
14342504930963
151825a724b2d8
hexc2553434f4b

13354450243403 has 4 divisors (see below), whose sum is σ = 13373776510728. Its totient is φ = 13335123976080.

The previous prime is 13354450243367. The next prime is 13354450243423. The reversal of 13354450243403 is 30434205445331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13354450243403 - 210 = 13354450242379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13354450243423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9663132626 + ... + 9663134007.

It is an arithmetic number, because the mean of its divisors is an integer number (3343444127682).

Almost surely, 213354450243403 is an apocalyptic number.

13354450243403 is a deficient number, since it is larger than the sum of its proper divisors (19326267325).

13354450243403 is an equidigital number, since it uses as much as digits as its factorization.

13354450243403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19326267324.

The product of its (nonzero) digits is 1036800, while the sum is 41.

Adding to 13354450243403 its reverse (30434205445331), we get a palindrome (43788655688734).

The spelling of 13354450243403 in words is "thirteen trillion, three hundred fifty-four billion, four hundred fifty million, two hundred forty-three thousand, four hundred three".

Divisors: 1 691 19326266633 13354450243403