Base | Representation |
---|---|
bin | 111110001100000110… |
… | …1000001111110100011 |
3 | 110202201022222202000121 |
4 | 1330120031001332203 |
5 | 4142002303232311 |
6 | 141204013101111 |
7 | 12435331511620 |
oct | 1743015017643 |
9 | 422638882017 |
10 | 133550055331 |
11 | 51702585260 |
12 | 21a71787797 |
13 | c7945187a4 |
14 | 666cb77347 |
15 | 371985bb71 |
hex | 1f18341fa3 |
133550055331 has 32 divisors (see below), whose sum is σ = 172122402816. Its totient is φ = 100563120000.
The previous prime is 133550055329. The next prime is 133550055341.
133550055331 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 133550055331 - 21 = 133550055329 is a prime.
It is a super-2 number, since 2×1335500553312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (133550055341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1633381 + ... + 1713193.
It is an arithmetic number, because the mean of its divisors is an integer number (5378825088).
Almost surely, 2133550055331 is an apocalyptic number.
133550055331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
133550055331 is a deficient number, since it is larger than the sum of its proper divisors (38572347485).
133550055331 is a wasteful number, since it uses less digits than its factorization.
133550055331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80563.
The product of its (nonzero) digits is 50625, while the sum is 34.
The spelling of 133550055331 in words is "one hundred thirty-three billion, five hundred fifty million, fifty-five thousand, three hundred thirty-one".
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