Base | Representation |
---|---|
bin | 1100001001010111011001… |
… | …1100000110001011110011 |
3 | 1202021201200201122120202012 |
4 | 3002111312130012023303 |
5 | 3222302110320300430 |
6 | 44223115412313135 |
7 | 2545604231246621 |
oct | 302256634061363 |
9 | 52251621576665 |
10 | 13355040400115 |
11 | 4289928160277 |
12 | 15b83680127ab |
13 | 75b4b488c2cb |
14 | 34255d074511 |
15 | 1825dde72695 |
hex | c25767062f3 |
13355040400115 has 16 divisors (see below), whose sum is σ = 16312183081920. Its totient is φ = 10494394727040.
The previous prime is 13355040400067. The next prime is 13355040400151. The reversal of 13355040400115 is 51100404055331.
13355040400115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13355040400115 - 210 = 13355040399091 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69829844 + ... + 70020833.
It is an arithmetic number, because the mean of its divisors is an integer number (1019511442620).
Almost surely, 213355040400115 is an apocalyptic number.
13355040400115 is a deficient number, since it is larger than the sum of its proper divisors (2957142681805).
13355040400115 is a wasteful number, since it uses less digits than its factorization.
13355040400115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139851022.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 13355040400115 its reverse (51100404055331), we get a palindrome (64455444455446).
The spelling of 13355040400115 in words is "thirteen trillion, three hundred fifty-five billion, forty million, four hundred thousand, one hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •