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13355040400115 = 571269139850677
BaseRepresentation
bin1100001001010111011001…
…1100000110001011110011
31202021201200201122120202012
43002111312130012023303
53222302110320300430
644223115412313135
72545604231246621
oct302256634061363
952251621576665
1013355040400115
114289928160277
1215b83680127ab
1375b4b488c2cb
1434255d074511
151825dde72695
hexc25767062f3

13355040400115 has 16 divisors (see below), whose sum is σ = 16312183081920. Its totient is φ = 10494394727040.

The previous prime is 13355040400067. The next prime is 13355040400151. The reversal of 13355040400115 is 51100404055331.

13355040400115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13355040400115 - 210 = 13355040399091 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69829844 + ... + 70020833.

It is an arithmetic number, because the mean of its divisors is an integer number (1019511442620).

Almost surely, 213355040400115 is an apocalyptic number.

13355040400115 is a deficient number, since it is larger than the sum of its proper divisors (2957142681805).

13355040400115 is a wasteful number, since it uses less digits than its factorization.

13355040400115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 139851022.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 13355040400115 its reverse (51100404055331), we get a palindrome (64455444455446).

The spelling of 13355040400115 in words is "thirteen trillion, three hundred fifty-five billion, forty million, four hundred thousand, one hundred fifteen".

Divisors: 1 5 71 269 355 1345 19099 95495 139850677 699253385 9929398067 37619832113 49646990335 188099160565 2671008080023 13355040400115