Base | Representation |
---|---|
bin | 1100001001010111101011… |
… | …0101011100110110110001 |
3 | 1202021201212212102202000221 |
4 | 3002111322311130312301 |
5 | 3222302233210433231 |
6 | 44223131005213041 |
7 | 2545606115204002 |
oct | 302257265346661 |
9 | 52251785382027 |
10 | 13355114155441 |
11 | 4289965856793 |
12 | 15b8388861181 |
13 | 75b4c6c44206 |
14 | 342568b931a9 |
15 | 1825e5690d11 |
hex | c257ad5cdb1 |
13355114155441 has 4 divisors (see below), whose sum is σ = 13355773069300. Its totient is φ = 13354455241584.
The previous prime is 13355114155381. The next prime is 13355114155447. The reversal of 13355114155441 is 14455141155331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5349524913216 + 8005589242225 = 2312904^2 + 2829415^2 .
It is a cyclic number.
It is not a de Polignac number, because 13355114155441 - 233 = 13346524220849 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13355114155447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 329426526 + ... + 329467063.
It is an arithmetic number, because the mean of its divisors is an integer number (3338943267325).
Almost surely, 213355114155441 is an apocalyptic number.
It is an amenable number.
13355114155441 is a deficient number, since it is larger than the sum of its proper divisors (658913859).
13355114155441 is an equidigital number, since it uses as much as digits as its factorization.
13355114155441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 658913858.
The product of its digits is 360000, while the sum is 43.
The spelling of 13355114155441 in words is "thirteen trillion, three hundred fifty-five billion, one hundred fourteen million, one hundred fifty-five thousand, four hundred forty-one".
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