13355114333153 has 4 divisors (see below), whose sum is σ = 13355294349360. Its totient is φ = 13354934316948.

The previous prime is 13355114333117. The next prime is 13355114333173. The reversal of 13355114333153 is 35133341155331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13355114333153 - 2³⁰ = 13354040591329 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13355114333153.

It is not an unprimeable number, because it can be changed into a prime (13355114333173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89896775 + ... + 90045212.

It is an arithmetic number, because the mean of its divisors is an integer number (3338823587340).

Almost surely, 2^{13355114333153} is an apocalyptic number.

It is an amenable number.

13355114333153 is a deficient number, since it is larger than the sum of its proper divisors (180016207).

13355114333153 is an equidigital number, since it uses as much as digits as its factorization.

13355114333153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 180016206.

The product of its digits is 364500, while the sum is 41.

Adding to 13355114333153 its reverse (35133341155331), we get a palindrome (48488455488484).

The spelling of 13355114333153 in words is "thirteen trillion, three hundred fifty-five billion, one hundred fourteen million, three hundred thirty-three thousand, one hundred fifty-three".