Base | Representation |
---|---|
bin | 1100001001011001001010… |
… | …1010111001101110100110 |
3 | 1202021202220201220011001110 |
4 | 3002112102222321232212 |
5 | 3222304043043341202 |
6 | 44223234412205450 |
7 | 2545622042200554 |
oct | 302262252715646 |
9 | 52252821804043 |
10 | 13355514043302 |
11 | 428a050555422 |
12 | 15b847a769886 |
13 | 75b55ba46752 |
14 | 3425a5d28bd4 |
15 | 18261a83126c |
hex | c2592ab9ba6 |
13355514043302 has 16 divisors (see below), whose sum is σ = 26711151918912. Its totient is φ = 4451817375720.
The previous prime is 13355514043247. The next prime is 13355514043303. The reversal of 13355514043302 is 20334041555331.
13355514043302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13355514043303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3727008 + ... + 6371939.
It is an arithmetic number, because the mean of its divisors is an integer number (1669446994932).
Almost surely, 213355514043302 is an apocalyptic number.
13355514043302 is an abundant number, since it is smaller than the sum of its proper divisors (13355637875610).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13355514043302 is a wasteful number, since it uses less digits than its factorization.
13355514043302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10319363.
The product of its (nonzero) digits is 324000, while the sum is 39.
Adding to 13355514043302 its reverse (20334041555331), we get a palindrome (33689555598633).
The spelling of 13355514043302 in words is "thirteen trillion, three hundred fifty-five billion, five hundred fourteen million, forty-three thousand, three hundred two".
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