Base | Representation |
---|---|
bin | 11110010111101000011111… |
… | …100111000101011100110010 |
3 | 122111220201200222222210210210 |
4 | 132113220133213011130302 |
5 | 120001313441331420032 |
6 | 1152023035225204550 |
7 | 40063532462620221 |
oct | 3627503747053462 |
9 | 574821628883723 |
10 | 133565423310642 |
11 | 39615861462a74 |
12 | 12b91a5a030756 |
13 | 596b21c43248b |
14 | 24da85b140cb8 |
15 | 10695233452cc |
hex | 797a1f9c5732 |
133565423310642 has 32 divisors (see below), whose sum is σ = 281877200173440. Its totient is φ = 42107581746560.
The previous prime is 133565423310637. The next prime is 133565423310643. The reversal of 133565423310642 is 246013324565331.
It is a junction number, because it is equal to n+sod(n) for n = 133565423310591 and 133565423310600.
It is not an unprimeable number, because it can be changed into a prime (133565423310643) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5437433709 + ... + 5437458272.
It is an arithmetic number, because the mean of its divisors is an integer number (8808662505420).
Almost surely, 2133565423310642 is an apocalyptic number.
133565423310642 is an abundant number, since it is smaller than the sum of its proper divisors (148311776862798).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133565423310642 is a wasteful number, since it uses less digits than its factorization.
133565423310642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10874892098.
The product of its (nonzero) digits is 4665600, while the sum is 48.
Adding to 133565423310642 its reverse (246013324565331), we get a palindrome (379578747875973).
The spelling of 133565423310642 in words is "one hundred thirty-three trillion, five hundred sixty-five billion, four hundred twenty-three million, three hundred ten thousand, six hundred forty-two".
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