Base | Representation |
---|---|
bin | 11110010111101000101100… |
… | …101001011100001110110001 |
3 | 122111220202021020120000011122 |
4 | 132113220230221130032301 |
5 | 120001314413330011144 |
6 | 1152023113041152025 |
7 | 40063541060000033 |
oct | 3627505451341661 |
9 | 574822236500148 |
10 | 133565642032049 |
11 | 39615963972667 |
12 | 12b91abb32b615 |
13 | 596b255842c26 |
14 | 24da87c1d7c53 |
15 | 106953764b7ee |
hex | 797a2ca5c3b1 |
133565642032049 has 2 divisors, whose sum is σ = 133565642032050. Its totient is φ = 133565642032048.
The previous prime is 133565642031979. The next prime is 133565642032093. The reversal of 133565642032049 is 940230246565331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116122865665024 + 17442776367025 = 10776032^2 + 4176455^2 .
It is a cyclic number.
It is not a de Polignac number, because 133565642032049 - 212 = 133565642027953 is a prime.
It is not a weakly prime, because it can be changed into another prime (133565642032099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66782821016024 + 66782821016025.
It is an arithmetic number, because the mean of its divisors is an integer number (66782821016025).
Almost surely, 2133565642032049 is an apocalyptic number.
It is an amenable number.
133565642032049 is a deficient number, since it is larger than the sum of its proper divisors (1).
133565642032049 is an equidigital number, since it uses as much as digits as its factorization.
133565642032049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13996800, while the sum is 53.
The spelling of 133565642032049 in words is "one hundred thirty-three trillion, five hundred sixty-five billion, six hundred forty-two million, thirty-two thousand, forty-nine".
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