133568026049 has 4 divisors (see below), whose sum is σ = 133572415536. Its totient is φ = 133563636564.

The previous prime is 133568026037. The next prime is 133568026073. The reversal of 133568026049 is 940620865331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133568026049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133568025994 and 133568026012.

It is not an unprimeable number, because it can be changed into a prime (133568026849) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2148779 + ... + 2210064.

It is an arithmetic number, because the mean of its divisors is an integer number (33393103884).

Almost surely, 2^133568026049 is an apocalyptic number.

It is an amenable number.

133568026049 is a deficient number, since it is larger than the sum of its proper divisors (4389487).

133568026049 is an equidigital number, since it uses as much as digits as its factorization.

133568026049 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4389486.

The product of its (nonzero) digits is 933120, while the sum is 47.

The spelling of 133568026049 in words is "one hundred thirty-three billion, five hundred sixty-eight million, twenty-six thousand, forty-nine".