Base | Representation |
---|---|
bin | 1100001001110000100101… |
… | …0001011001100100111011 |
3 | 1202022101010201210120200222 |
4 | 3002130021101121210323 |
5 | 3222404430444022021 |
6 | 44230154200450255 |
7 | 2546233554646334 |
oct | 302341121314473 |
9 | 52271121716628 |
10 | 13361798814011 |
11 | 42917860a86aa |
12 | 15b973347998b |
13 | 75c020b0a49b |
14 | 342a008a528b |
15 | 18288746a6ab |
hex | c270945993b |
13361798814011 has 2 divisors, whose sum is σ = 13361798814012. Its totient is φ = 13361798814010.
The previous prime is 13361798813981. The next prime is 13361798814101. The reversal of 13361798814011 is 11041889716331.
Together with next prime (13361798814101) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13361798814011 is a prime.
It is a super-2 number, since 2×133617988140112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13361798817011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6680899407005 + 6680899407006.
It is an arithmetic number, because the mean of its divisors is an integer number (6680899407006).
Almost surely, 213361798814011 is an apocalyptic number.
13361798814011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13361798814011 is an equidigital number, since it uses as much as digits as its factorization.
13361798814011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 53.
The spelling of 13361798814011 in words is "thirteen trillion, three hundred sixty-one billion, seven hundred ninety-eight million, eight hundred fourteen thousand, eleven".
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