Base | Representation |
---|---|
bin | 11110011000111100001100… |
… | …111010111010100101010001 |
3 | 122112020022200221110201002222 |
4 | 132120330030322322211101 |
5 | 120004302030314230441 |
6 | 1152132222105350425 |
7 | 40103164013423102 |
oct | 3630741472724521 |
9 | 575208627421088 |
10 | 133655304055121 |
11 | 3964a994830682 |
12 | 12ba7362a98415 |
13 | 597684462b654 |
14 | 2500d462783a9 |
15 | 106ba33eb6d4b |
hex | 798f0ceba951 |
133655304055121 has 2 divisors, whose sum is σ = 133655304055122. Its totient is φ = 133655304055120.
The previous prime is 133655304055079. The next prime is 133655304055171. The reversal of 133655304055121 is 121550403556331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111167184652225 + 22488119402896 = 10543585^2 + 4742164^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133655304055121 is a prime.
It is not a weakly prime, because it can be changed into another prime (133655304055171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66827652027560 + 66827652027561.
It is an arithmetic number, because the mean of its divisors is an integer number (66827652027561).
Almost surely, 2133655304055121 is an apocalyptic number.
It is an amenable number.
133655304055121 is a deficient number, since it is larger than the sum of its proper divisors (1).
133655304055121 is an equidigital number, since it uses as much as digits as its factorization.
133655304055121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 810000, while the sum is 44.
The spelling of 133655304055121 in words is "one hundred thirty-three trillion, six hundred fifty-five billion, three hundred four million, fifty-five thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •