Base | Representation |
---|---|
bin | 111110010001110000… |
… | …1101100000111101011 |
3 | 110210012120102221211121 |
4 | 1330203201230013223 |
5 | 4142344421121303 |
6 | 141234520440111 |
7 | 12443126262226 |
oct | 1744341540753 |
9 | 423176387747 |
10 | 133740020203 |
11 | 5179a833719 |
12 | 21b05319037 |
13 | c7c499b23a |
14 | 668a0a65bd |
15 | 372b3829bd |
hex | 1f2386c1eb |
133740020203 has 2 divisors, whose sum is σ = 133740020204. Its totient is φ = 133740020202.
The previous prime is 133740020173. The next prime is 133740020207. The reversal of 133740020203 is 302020047331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133740020203 - 29 = 133740019691 is a prime.
It is a super-2 number, since 2×1337400202032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133740020207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66870010101 + 66870010102.
It is an arithmetic number, because the mean of its divisors is an integer number (66870010102).
Almost surely, 2133740020203 is an apocalyptic number.
133740020203 is a deficient number, since it is larger than the sum of its proper divisors (1).
133740020203 is an equidigital number, since it uses as much as digits as its factorization.
133740020203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 25.
Adding to 133740020203 its reverse (302020047331), we get a palindrome (435760067534).
The spelling of 133740020203 in words is "one hundred thirty-three billion, seven hundred forty million, twenty thousand, two hundred three".
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