Base | Representation |
---|---|
bin | 111110010001110000… |
… | …1101100001000011011 |
3 | 110210012120102221220101 |
4 | 1330203201230020123 |
5 | 4142344421122001 |
6 | 141234520440231 |
7 | 12443126262325 |
oct | 1744341541033 |
9 | 423176387811 |
10 | 133740020251 |
11 | 5179a833762 |
12 | 21b05319077 |
13 | c7c499b276 |
14 | 668a0a6615 |
15 | 372b382a01 |
hex | 1f2386c21b |
133740020251 has 2 divisors, whose sum is σ = 133740020252. Its totient is φ = 133740020250.
The previous prime is 133740020207. The next prime is 133740020257. The reversal of 133740020251 is 152020047331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133740020251 is a prime.
It is not a weakly prime, because it can be changed into another prime (133740020257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66870010125 + 66870010126.
It is an arithmetic number, because the mean of its divisors is an integer number (66870010126).
Almost surely, 2133740020251 is an apocalyptic number.
133740020251 is a deficient number, since it is larger than the sum of its proper divisors (1).
133740020251 is an equidigital number, since it uses as much as digits as its factorization.
133740020251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 28.
Adding to 133740020251 its reverse (152020047331), we get a palindrome (285760067582).
The spelling of 133740020251 in words is "one hundred thirty-three billion, seven hundred forty million, twenty thousand, two hundred fifty-one".
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