Base | Representation |
---|---|
bin | 11000111011100000… |
… | …00111100000100001 |
3 | 1021112202110102121222 |
4 | 30131300013200201 |
5 | 204402304223232 |
6 | 10052030424425 |
7 | 652445405660 |
oct | 143560074041 |
9 | 37482412558 |
10 | 13384054817 |
11 | 5748a4a531 |
12 | 2716362115 |
13 | 1353b1c683 |
14 | 90d77cdd7 |
15 | 535015d12 |
hex | 31dc07821 |
13384054817 has 4 divisors (see below), whose sum is σ = 15296062656. Its totient is φ = 11472046980.
The previous prime is 13384054811. The next prime is 13384054823. The reversal of 13384054817 is 71845048331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (13384054811) and next prime (13384054823).
It is a cyclic number.
It is not a de Polignac number, because 13384054817 - 26 = 13384054753 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13384054811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 956003909 + ... + 956003922.
It is an arithmetic number, because the mean of its divisors is an integer number (3824015664).
Almost surely, 213384054817 is an apocalyptic number.
It is an amenable number.
13384054817 is a deficient number, since it is larger than the sum of its proper divisors (1912007839).
13384054817 is an equidigital number, since it uses as much as digits as its factorization.
13384054817 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1912007838.
The product of its (nonzero) digits is 322560, while the sum is 44.
The spelling of 13384054817 in words is "thirteen billion, three hundred eighty-four million, fifty-four thousand, eight hundred seventeen".
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