13384134113 has 4 divisors (see below), whose sum is σ = 15296153280. Its totient is φ = 11472114948.

The previous prime is 13384134083. The next prime is 13384134133. The reversal of 13384134113 is 31143148331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31143148331 = 1181 ⋅26370151.

It is not a de Polignac number, because 13384134113 - 2¹² = 13384130017 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13384134113.

It is not an unprimeable number, because it can be changed into a prime (13384134133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 956009573 + ... + 956009586.

It is an arithmetic number, because the mean of its divisors is an integer number (3824038320).

Almost surely, 2^13384134113 is an apocalyptic number.

It is an amenable number.

13384134113 is a deficient number, since it is larger than the sum of its proper divisors (1912019167).

13384134113 is an equidigital number, since it uses as much as digits as its factorization.

13384134113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1912019166.

The product of its digits is 10368, while the sum is 32.

The spelling of 13384134113 in words is "thirteen billion, three hundred eighty-four million, one hundred thirty-four thousand, one hundred thirteen".