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1339131403 is a prime number
BaseRepresentation
bin100111111010001…
…1000011000001011
310110022210220221101
41033310120120023
510220304201103
6340514122231
745120300121
oct11764303013
93408726841
101339131403
116279a5275
12314580377
1318458935c
14c9bc9911
157c86ea1d
hex4fd1860b

1339131403 has 2 divisors, whose sum is σ = 1339131404. Its totient is φ = 1339131402.

The previous prime is 1339131383. The next prime is 1339131407. The reversal of 1339131403 is 3041319331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1339131403 - 229 = 802260491 is a prime.

It is not a weakly prime, because it can be changed into another prime (1339131407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669565701 + 669565702.

It is an arithmetic number, because the mean of its divisors is an integer number (669565702).

Almost surely, 21339131403 is an apocalyptic number.

1339131403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1339131403 is an equidigital number, since it uses as much as digits as its factorization.

1339131403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 28.

The square root of 1339131403 is about 36594.1443813078. The cubic root of 1339131403 is about 1102.2355096602.

The spelling of 1339131403 in words is "one billion, three hundred thirty-nine million, one hundred thirty-one thousand, four hundred three".