Base | Representation |
---|---|
bin | 1111111101110… |
… | …00010011000001 |
3 | 100100000001020101 |
4 | 13332320103001 |
5 | 233241032113 |
6 | 21142242401 |
7 | 3214223035 |
oct | 776702301 |
9 | 310001211 |
10 | 133924033 |
11 | 69662121 |
12 | 38a26401 |
13 | 219908b9 |
14 | 13b021c5 |
15 | bb562dd |
hex | 7fb84c1 |
133924033 has 2 divisors, whose sum is σ = 133924034. Its totient is φ = 133924032.
The previous prime is 133924013. The next prime is 133924073. The reversal of 133924033 is 330429331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98545329 + 35378704 = 9927^2 + 5948^2 .
It is an emirp because it is prime and its reverse (330429331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133924033 - 213 = 133915841 is a prime.
It is a super-2 number, since 2×1339240332 = 35871293229970178, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133923992 and 133924010.
It is not a weakly prime, because it can be changed into another prime (133924003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66962016 + 66962017.
It is an arithmetic number, because the mean of its divisors is an integer number (66962017).
Almost surely, 2133924033 is an apocalyptic number.
It is an amenable number.
133924033 is a deficient number, since it is larger than the sum of its proper divisors (1).
133924033 is an equidigital number, since it uses as much as digits as its factorization.
133924033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 28.
The square root of 133924033 is about 11572.5551629707. Note that the first 3 decimals coincide. The cubic root of 133924033 is about 511.6262747679.
The spelling of 133924033 in words is "one hundred thirty-three million, nine hundred twenty-four thousand, thirty-three".
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