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133934981651 is a prime number
BaseRepresentation
bin111110010111100100…
…1011010001000010011
3110210201011022000122222
41330233021122020103
54143244323403101
6141310123251255
712451014363032
oct1745711321023
9423634260588
10133934981651
115188a895089
1221b5a679b2b
13c8261b0043
1466a7d36719
15373d54401b
hex1f2f25a213

133934981651 has 2 divisors, whose sum is σ = 133934981652. Its totient is φ = 133934981650.

The previous prime is 133934981639. The next prime is 133934981689. The reversal of 133934981651 is 156189439331.

It is a weak prime.

It is an emirp because it is prime and its reverse (156189439331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133934981651 - 218 = 133934719507 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133934981593 and 133934981602.

It is not a weakly prime, because it can be changed into another prime (133934980651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66967490825 + 66967490826.

It is an arithmetic number, because the mean of its divisors is an integer number (66967490826).

Almost surely, 2133934981651 is an apocalyptic number.

133934981651 is a deficient number, since it is larger than the sum of its proper divisors (1).

133934981651 is an equidigital number, since it uses as much as digits as its factorization.

133934981651 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2099520, while the sum is 53.

The spelling of 133934981651 in words is "one hundred thirty-three billion, nine hundred thirty-four million, nine hundred eighty-one thousand, six hundred fifty-one".