Base | Representation |
---|---|
bin | 1100001011111110111110… |
… | …1011101011010000001011 |
3 | 1202110000210201121101201010 |
4 | 3002333233223223100023 |
5 | 3224021222143401303 |
6 | 44255515223255003 |
7 | 2552056043244054 |
oct | 302775753532013 |
9 | 52400721541633 |
10 | 13400024200203 |
11 | 42a6a11361063 |
12 | 1605020baa463 |
13 | 76280331a8b4 |
14 | 3447c94c772b |
15 | 183873260c03 |
hex | c2fefaeb40b |
13400024200203 has 32 divisors (see below), whose sum is σ = 19570443393600. Its totient is φ = 8117754494976.
The previous prime is 13400024200133. The next prime is 13400024200231. The reversal of 13400024200203 is 30200242000431.
It is not a de Polignac number, because 13400024200203 - 213 = 13400024192011 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13400024200203.
It is not an unprimeable number, because it can be changed into a prime (13400024200273) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 105520875 + ... + 105647787.
It is an arithmetic number, because the mean of its divisors is an integer number (611576356050).
Almost surely, 213400024200203 is an apocalyptic number.
13400024200203 is a deficient number, since it is larger than the sum of its proper divisors (6170419193397).
13400024200203 is a wasteful number, since it uses less digits than its factorization.
13400024200203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 198351.
The product of its (nonzero) digits is 1152, while the sum is 21.
Adding to 13400024200203 its reverse (30200242000431), we get a palindrome (43600266200634).
The spelling of 13400024200203 in words is "thirteen trillion, four hundred billion, twenty-four million, two hundred thousand, two hundred three".
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