13400025055051 has 4 divisors (see below), whose sum is σ = 13400032778704. Its totient is φ = 13400017331400.

The previous prime is 13400025055037. The next prime is 13400025055061. The reversal of 13400025055051 is 15055052000431.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13400025055051 - 2³⁹ = 12850269241163 is a prime.

It is a super-2 number, since 2×13400025055051² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13400025055061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85441 + ... + 5177581.

It is an arithmetic number, because the mean of its divisors is an integer number (3350008194676).

Almost surely, 2^{13400025055051} is an apocalyptic number.

13400025055051 is a deficient number, since it is larger than the sum of its proper divisors (7723653).

13400025055051 is an equidigital number, since it uses as much as digits as its factorization.

13400025055051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7723652.

The product of its (nonzero) digits is 15000, while the sum is 31.

Adding to 13400025055051 its reverse (15055052000431), we get a palindrome (28455077055482).

The spelling of 13400025055051 in words is "thirteen trillion, four hundred billion, twenty-five million, fifty-five thousand, fifty-one".