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134001123011963 is a prime number
BaseRepresentation
bin11110011101111110010001…
…010101100010110101111011
3122120110101022122211220111122
4132131332101111202311323
5120030433244442340323
61152555133250015455
740140155514153134
oct3635762125426573
9576411278756448
10134001123011963
11397736145a1359
1213042394b7758b
1359a0336c2a92c
14251399070ac8b
151075a23e32ec8
hex79df91562d7b

134001123011963 has 2 divisors, whose sum is σ = 134001123011964. Its totient is φ = 134001123011962.

The previous prime is 134001123011957. The next prime is 134001123012037. The reversal of 134001123011963 is 369110321100431.

It is a weak prime.

It is an emirp because it is prime and its reverse (369110321100431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134001123011963 - 222 = 134001118817659 is a prime.

It is a super-2 number, since 2×1340011230119632 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134001123014963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67000561505981 + 67000561505982.

It is an arithmetic number, because the mean of its divisors is an integer number (67000561505982).

Almost surely, 2134001123011963 is an apocalyptic number.

134001123011963 is a deficient number, since it is larger than the sum of its proper divisors (1).

134001123011963 is an equidigital number, since it uses as much as digits as its factorization.

134001123011963 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 35.

The spelling of 134001123011963 in words is "one hundred thirty-four trillion, one billion, one hundred twenty-three million, eleven thousand, nine hundred sixty-three".