Base | Representation |
---|---|
bin | 1100001011111111010011… |
… | …1111001110001111100011 |
3 | 1202110001000221002120122211 |
4 | 3002333310333032033203 |
5 | 3224021412440212324 |
6 | 44255532123142551 |
7 | 2552061203644612 |
oct | 302776477161743 |
9 | 52401027076584 |
10 | 13400113210339 |
11 | 42a6a57626759 |
12 | 1605046974a57 |
13 | 7628188b410b |
14 | 3447d7257879 |
15 | 18387ae94294 |
hex | c2ff4fce3e3 |
13400113210339 has 2 divisors, whose sum is σ = 13400113210340. Its totient is φ = 13400113210338.
The previous prime is 13400113210301. The next prime is 13400113210349. The reversal of 13400113210339 is 93301231100431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13400113210339 - 29 = 13400113209827 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13400113210339.
It is not a weakly prime, because it can be changed into another prime (13400113210349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700056605169 + 6700056605170.
It is an arithmetic number, because the mean of its divisors is an integer number (6700056605170).
Almost surely, 213400113210339 is an apocalyptic number.
13400113210339 is a deficient number, since it is larger than the sum of its proper divisors (1).
13400113210339 is an equidigital number, since it uses as much as digits as its factorization.
13400113210339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 31.
The spelling of 13400113210339 in words is "thirteen trillion, four hundred billion, one hundred thirteen million, two hundred ten thousand, three hundred thirty-nine".
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