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13400140024129 is a prime number
BaseRepresentation
bin1100001011111111011010…
…0101100000100101000001
31202110001002210112212021011
43002333312211200211001
53224021441321233004
644255534522000521
72552061650603125
oct302776645404501
952401083485234
1013400140024129
1142a6a70780311
121605053946141
13762821311a71
143447daa37585
1518387d4de004
hexc2ff6960941

13400140024129 has 2 divisors, whose sum is σ = 13400140024130. Its totient is φ = 13400140024128.

The previous prime is 13400140024097. The next prime is 13400140024133. The reversal of 13400140024129 is 92142004100431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12817459701904 + 582680322225 = 3580148^2 + 763335^2 .

It is a cyclic number.

It is not a de Polignac number, because 13400140024129 - 25 = 13400140024097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13400140024129.

It is not a weakly prime, because it can be changed into another prime (13400140024169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700070012064 + 6700070012065.

It is an arithmetic number, because the mean of its divisors is an integer number (6700070012065).

Almost surely, 213400140024129 is an apocalyptic number.

It is an amenable number.

13400140024129 is a deficient number, since it is larger than the sum of its proper divisors (1).

13400140024129 is an equidigital number, since it uses as much as digits as its factorization.

13400140024129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

The spelling of 13400140024129 in words is "thirteen trillion, four hundred billion, one hundred forty million, twenty-four thousand, one hundred twenty-nine".