Base | Representation |
---|---|
bin | 1100001011111111011010… |
… | …0101100000100101000001 |
3 | 1202110001002210112212021011 |
4 | 3002333312211200211001 |
5 | 3224021441321233004 |
6 | 44255534522000521 |
7 | 2552061650603125 |
oct | 302776645404501 |
9 | 52401083485234 |
10 | 13400140024129 |
11 | 42a6a70780311 |
12 | 1605053946141 |
13 | 762821311a71 |
14 | 3447daa37585 |
15 | 18387d4de004 |
hex | c2ff6960941 |
13400140024129 has 2 divisors, whose sum is σ = 13400140024130. Its totient is φ = 13400140024128.
The previous prime is 13400140024097. The next prime is 13400140024133. The reversal of 13400140024129 is 92142004100431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12817459701904 + 582680322225 = 3580148^2 + 763335^2 .
It is a cyclic number.
It is not a de Polignac number, because 13400140024129 - 25 = 13400140024097 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13400140024129.
It is not a weakly prime, because it can be changed into another prime (13400140024169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700070012064 + 6700070012065.
It is an arithmetic number, because the mean of its divisors is an integer number (6700070012065).
Almost surely, 213400140024129 is an apocalyptic number.
It is an amenable number.
13400140024129 is a deficient number, since it is larger than the sum of its proper divisors (1).
13400140024129 is an equidigital number, since it uses as much as digits as its factorization.
13400140024129 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 13400140024129 in words is "thirteen trillion, four hundred billion, one hundred forty million, twenty-four thousand, one hundred twenty-nine".
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