Base | Representation |
---|---|
bin | 11110011101111110100010… |
… | …000010110011000000100001 |
3 | 122120110102001012021112021121 |
4 | 132131332202002303000201 |
5 | 120030434333221410423 |
6 | 1152555221141452241 |
7 | 40140165456514663 |
oct | 3635764202630041 |
9 | 576412035245247 |
10 | 134001403310113 |
11 | 39773748839519 |
12 | 13042452a11081 |
13 | 59a038001ac21 |
14 | 25139b9a32533 |
15 | 1075a3d84e45d |
hex | 79dfa20b3021 |
134001403310113 has 2 divisors, whose sum is σ = 134001403310114. Its totient is φ = 134001403310112.
The previous prime is 134001403310063. The next prime is 134001403310147. The reversal of 134001403310113 is 311013304100431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113568942138129 + 20432461171984 = 10656873^2 + 4520228^2 .
It is a cyclic number.
It is not a de Polignac number, because 134001403310113 - 29 = 134001403309601 is a prime.
It is not a weakly prime, because it can be changed into another prime (134001403310153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67000701655056 + 67000701655057.
It is an arithmetic number, because the mean of its divisors is an integer number (67000701655057).
Almost surely, 2134001403310113 is an apocalyptic number.
It is an amenable number.
134001403310113 is a deficient number, since it is larger than the sum of its proper divisors (1).
134001403310113 is an equidigital number, since it uses as much as digits as its factorization.
134001403310113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 134001403310113 its reverse (311013304100431), we get a palindrome (445014707410544).
The spelling of 134001403310113 in words is "one hundred thirty-four trillion, one billion, four hundred three million, three hundred ten thousand, one hundred thirteen".
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