Base | Representation |
---|---|
bin | 10011011111111111100… |
… | …000011001010101111011 |
3 | 11202002211101212220000121 |
4 | 103133333200121111323 |
5 | 133423331001332142 |
6 | 2503333011314111 |
7 | 165545660625145 |
oct | 23377740312573 |
9 | 4662741786017 |
10 | 1340021511547 |
11 | 477333233174 |
12 | 1978565ab937 |
13 | 9949576c114 |
14 | 48c00955c95 |
15 | 24ccc75ac67 |
hex | 137ff81957b |
1340021511547 has 2 divisors, whose sum is σ = 1340021511548. Its totient is φ = 1340021511546.
The previous prime is 1340021511529. The next prime is 1340021511553. The reversal of 1340021511547 is 7451151200431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1340021511547 - 27 = 1340021511419 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340021611547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670010755773 + 670010755774.
It is an arithmetic number, because the mean of its divisors is an integer number (670010755774).
Almost surely, 21340021511547 is an apocalyptic number.
1340021511547 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340021511547 is an equidigital number, since it uses as much as digits as its factorization.
1340021511547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 34.
Adding to 1340021511547 its reverse (7451151200431), we get a palindrome (8791172711978).
The spelling of 1340021511547 in words is "one trillion, three hundred forty billion, twenty-one million, five hundred eleven thousand, five hundred forty-seven".
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