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13400452433 is a prime number
BaseRepresentation
bin11000111101011101…
…01010110101010001
31021120220022111221002
430132232222311101
5204421003434213
610053414111345
7653034652304
oct143656526521
937526274832
1013400452433
11575722a285
12271b94b555
1313573411c4
14911a0ab3b
155366a4658
hex31ebaad51

13400452433 has 2 divisors, whose sum is σ = 13400452434. Its totient is φ = 13400452432.

The previous prime is 13400452369. The next prime is 13400452459. The reversal of 13400452433 is 33425400431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10867645504 + 2532806929 = 104248^2 + 50327^2 .

It is a cyclic number.

It is not a de Polignac number, because 13400452433 - 26 = 13400452369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13400452396 and 13400452405.

It is not a weakly prime, because it can be changed into another prime (13400452463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700226216 + 6700226217.

It is an arithmetic number, because the mean of its divisors is an integer number (6700226217).

Almost surely, 213400452433 is an apocalyptic number.

It is an amenable number.

13400452433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13400452433 is an equidigital number, since it uses as much as digits as its factorization.

13400452433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 13400452433 its reverse (33425400431), we get a palindrome (46825852864).

The spelling of 13400452433 in words is "thirteen billion, four hundred million, four hundred fifty-two thousand, four hundred thirty-three".