Base | Representation |
---|---|
bin | 11000111101100001… |
… | …10101011101011011 |
3 | 1021120221101100211101 |
4 | 30132300311131123 |
5 | 204421130122001 |
6 | 10053434212231 |
7 | 653042535613 |
oct | 143660653533 |
9 | 37527340741 |
10 | 13401020251 |
11 | 5757587953 |
12 | 271bb84077 |
13 | 13574ac7a8 |
14 | 911b17a43 |
15 | 536767a01 |
hex | 31ec3575b |
13401020251 has 2 divisors, whose sum is σ = 13401020252. Its totient is φ = 13401020250.
The previous prime is 13401020201. The next prime is 13401020363. The reversal of 13401020251 is 15202010431.
It is a weak prime.
It is an emirp because it is prime and its reverse (15202010431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13401020251 - 27 = 13401020123 is a prime.
It is not a weakly prime, because it can be changed into another prime (13401020201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700510125 + 6700510126.
It is an arithmetic number, because the mean of its divisors is an integer number (6700510126).
Almost surely, 213401020251 is an apocalyptic number.
13401020251 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401020251 is an equidigital number, since it uses as much as digits as its factorization.
13401020251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 13401020251 its reverse (15202010431), we get a palindrome (28603030682).
The spelling of 13401020251 in words is "thirteen billion, four hundred one million, twenty thousand, two hundred fifty-one".
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