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1340103200113 = 7961927404413
BaseRepresentation
bin10011100000000100011…
…000000000110101110001
311202010001002121002200001
4103200010120000311301
5133424012404400423
62503345050230001
7165551002153216
oct23400430006561
94663032532601
101340103200113
11477375357a87
12197879a25301
13994a9670c52
1448c0b73bb0d
1524cd49e4cad
hex13804600d71

1340103200113 has 8 divisors (see below), whose sum is σ = 1359258934400. Its totient is φ = 1321002276048.

The previous prime is 1340103200101. The next prime is 1340103200147. The reversal of 1340103200113 is 3110023010431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340103200113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340133200113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13653306 + ... + 13751107.

It is an arithmetic number, because the mean of its divisors is an integer number (169907366800).

Almost surely, 21340103200113 is an apocalyptic number.

It is an amenable number.

1340103200113 is a deficient number, since it is larger than the sum of its proper divisors (19155734287).

1340103200113 is an equidigital number, since it uses as much as digits as its factorization.

1340103200113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27405111.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1340103200113 its reverse (3110023010431), we get a palindrome (4450126210544).

The spelling of 1340103200113 in words is "one trillion, three hundred forty billion, one hundred three million, two hundred thousand, one hundred thirteen".

Divisors: 1 79 619 48901 27404413 2164948627 16963331647 1340103200113