Base | Representation |
---|---|
bin | 10011100000000100011… |
… | …011111111010011100001 |
3 | 11202010001011120001102022 |
4 | 103200010123333103201 |
5 | 133424013141224101 |
6 | 2503345124431225 |
7 | 165551014054031 |
oct | 23400433772341 |
9 | 4663034501368 |
10 | 1340104242401 |
11 | 4773759aa081 |
12 | 19787a248515 |
13 | 994a99474a2 |
14 | 48c0b92d8c1 |
15 | 24cd4b4da1b |
hex | 138046ff4e1 |
1340104242401 has 2 divisors, whose sum is σ = 1340104242402. Its totient is φ = 1340104242400.
The previous prime is 1340104242397. The next prime is 1340104242479. The reversal of 1340104242401 is 1042424010431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1146235749376 + 193868493025 = 1070624^2 + 440305^2 .
It is a cyclic number.
It is not a de Polignac number, because 1340104242401 - 22 = 1340104242397 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340104242901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670052121200 + 670052121201.
It is an arithmetic number, because the mean of its divisors is an integer number (670052121201).
Almost surely, 21340104242401 is an apocalyptic number.
It is an amenable number.
1340104242401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340104242401 is an equidigital number, since it uses as much as digits as its factorization.
1340104242401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 26.
Adding to 1340104242401 its reverse (1042424010431), we get a palindrome (2382528252832).
The spelling of 1340104242401 in words is "one trillion, three hundred forty billion, one hundred four million, two hundred forty-two thousand, four hundred one".
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