13401142314403 has 4 divisors (see below), whose sum is σ = 13401239921128. Its totient is φ = 13401044707680.

The previous prime is 13401142314397. The next prime is 13401142314463. The reversal of 13401142314403 is 30441324110431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401142314403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13401142314463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48597126 + ... + 48872107.

It is an arithmetic number, because the mean of its divisors is an integer number (3350309980282).

Almost surely, 2^{13401142314403} is an apocalyptic number.

13401142314403 is a deficient number, since it is larger than the sum of its proper divisors (97606725).

13401142314403 is an equidigital number, since it uses as much as digits as its factorization.

13401142314403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 97606724.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13401142314403 its reverse (30441324110431), we get a palindrome (43842466424834).

The spelling of 13401142314403 in words is "thirteen trillion, four hundred one billion, one hundred forty-two million, three hundred fourteen thousand, four hundred three".