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134011443442 = 267005721721
BaseRepresentation
bin111110011001110110…
…1000101100011110010
3110210220111011200112011
41330303231011203302
54143423412142232
6141321454153134
712452633321512
oct1746355054362
9423814150464
10134011443442
1151919a69a48
1221b801b27aa
13c838ca1ac6
1466b415b842
1537450e9547
hex1f33b458f2

134011443442 has 4 divisors (see below), whose sum is σ = 201017165166. Its totient is φ = 67005721720.

The previous prime is 134011443439. The next prime is 134011443457. The reversal of 134011443442 is 244344110431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 244344110431 = 421580389811.

It can be written as a sum of positive squares in only one way, i.e., 88952466001 + 45058977441 = 298249^2 + 212271^2 .

It is a super-3 number, since 3×1340114434423 (a number of 34 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33502860859 + ... + 33502860862.

Almost surely, 2134011443442 is an apocalyptic number.

134011443442 is a deficient number, since it is larger than the sum of its proper divisors (67005721724).

134011443442 is an equidigital number, since it uses as much as digits as its factorization.

134011443442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67005721723.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 134011443442 its reverse (244344110431), we get a palindrome (378355553873).

The spelling of 134011443442 in words is "one hundred thirty-four billion, eleven million, four hundred forty-three thousand, four hundred forty-two".

Divisors: 1 2 67005721721 134011443442