1340121313523 has 2 divisors, whose sum is σ = 1340121313524. Its totient is φ = 1340121313522.

The previous prime is 1340121313519. The next prime is 1340121313537. The reversal of 1340121313523 is 3253131210431.

It is a weak prime.

It is an emirp because it is prime and its reverse (3253131210431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340121313523 - 2² = 1340121313519 is a prime.

It is a super-2 number, since 2×1340121313523² (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (1340121313513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670060656761 + 670060656762.

It is an arithmetic number, because the mean of its divisors is an integer number (670060656762).

Almost surely, 2^{1340121313523} is an apocalyptic number.

1340121313523 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340121313523 is an equidigital number, since it uses as much as digits as its factorization.

1340121313523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 1340121313523 its reverse (3253131210431), we get a palindrome (4593252523954).

The spelling of 1340121313523 in words is "one trillion, three hundred forty billion, one hundred twenty-one million, three hundred thirteen thousand, five hundred twenty-three".