1340123124433 has 2 divisors, whose sum is σ = 1340123124434. Its totient is φ = 1340123124432.

The previous prime is 1340123124407. The next prime is 1340123124481. The reversal of 1340123124433 is 3344213210431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 903845701264 + 436277423169 = 950708^2 + 660513^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340123124433 - 2³³ = 1331533189841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340123124395 and 1340123124404.

It is not a weakly prime, because it can be changed into another prime (1340123124233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670061562216 + 670061562217.

It is an arithmetic number, because the mean of its divisors is an integer number (670061562217).

Almost surely, 2^{1340123124433} is an apocalyptic number.

It is an amenable number.

1340123124433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340123124433 is an equidigital number, since it uses as much as digits as its factorization.

1340123124433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1340123124433 its reverse (3344213210431), we get a palindrome (4684336334864).

The spelling of 1340123124433 in words is "one trillion, three hundred forty billion, one hundred twenty-three million, one hundred twenty-four thousand, four hundred thirty-three".