Base | Representation |
---|---|
bin | 11110011110001000101101… |
… | …100101100110011011010001 |
3 | 122120111110021000001111022021 |
4 | 132132020231211212123101 |
5 | 120031124230101314413 |
6 | 1153004225545011441 |
7 | 40141033401330211 |
oct | 3636105545463321 |
9 | 576443230044267 |
10 | 134012334401233 |
11 | 39778348091022 |
12 | 130445a3783b81 |
13 | 59a1402899592 |
14 | 25143356c6241 |
15 | 1075e7d32b18d |
hex | 79e22d9666d1 |
134012334401233 has 8 divisors (see below), whose sum is σ = 135930079406016. Its totient is φ = 132095429600400.
The previous prime is 134012334401167. The next prime is 134012334401249. The reversal of 134012334401233 is 332104433210431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134012334401233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134012334401833) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 209729703 + ... + 210367708.
It is an arithmetic number, because the mean of its divisors is an integer number (16991259925752).
Almost surely, 2134012334401233 is an apocalyptic number.
It is an amenable number.
134012334401233 is a deficient number, since it is larger than the sum of its proper divisors (1917745004783).
134012334401233 is an equidigital number, since it uses as much as digits as its factorization.
134012334401233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 420101975.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 134012334401233 its reverse (332104433210431), we get a palindrome (466116767611664).
The spelling of 134012334401233 in words is "one hundred thirty-four trillion, twelve billion, three hundred thirty-four million, four hundred one thousand, two hundred thirty-three".
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