Base | Representation |
---|---|
bin | 111110011001111000… |
… | …0110010100011111011 |
3 | 110210220120000000011021 |
4 | 1330303300302203323 |
5 | 4143424134223303 |
6 | 141321531043311 |
7 | 12452644503643 |
oct | 1746360624373 |
9 | 423816000137 |
10 | 134012414203 |
11 | 5191a572328 |
12 | 21b805a0537 |
13 | c839251915 |
14 | 66b4331523 |
15 | 374523bebd |
hex | 1f33c328fb |
134012414203 has 8 divisors (see below), whose sum is σ = 136408809456. Its totient is φ = 131622453600.
The previous prime is 134012414177. The next prime is 134012414231. The reversal of 134012414203 is 302414210431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134012414203 is a prime.
It is a super-2 number, since 2×1340124142032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134012414903) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1566628 + ... + 1649953.
It is an arithmetic number, because the mean of its divisors is an integer number (17051101182).
Almost surely, 2134012414203 is an apocalyptic number.
134012414203 is a deficient number, since it is larger than the sum of its proper divisors (2396395253).
134012414203 is an equidigital number, since it uses as much as digits as its factorization.
134012414203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3217325.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 134012414203 its reverse (302414210431), we get a palindrome (436426624634).
The spelling of 134012414203 in words is "one hundred thirty-four billion, twelve million, four hundred fourteen thousand, two hundred three".
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