Base | Representation |
---|---|
bin | 1100001100000011100001… |
… | …0010110110101001011010 |
3 | 1202110010221121220212212210 |
4 | 3003000320102312221122 |
5 | 3224031221030230132 |
6 | 44300240142215550 |
7 | 2552131165106415 |
oct | 303007022665132 |
9 | 52403847825783 |
10 | 13401242430042 |
11 | 42a7486a89185 |
12 | 1605300b845b6 |
13 | 76296882585c |
14 | 3448a3200b7c |
15 | 1838e519cbcc |
hex | c30384b6a5a |
13401242430042 has 16 divisors (see below), whose sum is σ = 26802654842880. Its totient is φ = 4467052479552.
The previous prime is 13401242429957. The next prime is 13401242430047. The reversal of 13401242430042 is 24003424210431.
It is a junction number, because it is equal to n+sod(n) for n = 13401242429991 and 13401242430009.
It is not an unprimeable number, because it can be changed into a prime (13401242430047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6046042 + ... + 7959717.
It is an arithmetic number, because the mean of its divisors is an integer number (1675165927680).
Almost surely, 213401242430042 is an apocalyptic number.
13401242430042 is an abundant number, since it is smaller than the sum of its proper divisors (13401412412838).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13401242430042 is a wasteful number, since it uses less digits than its factorization.
13401242430042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14165237.
The product of its (nonzero) digits is 18432, while the sum is 30.
Adding to 13401242430042 its reverse (24003424210431), we get a palindrome (37404666640473).
The spelling of 13401242430042 in words is "thirteen trillion, four hundred one billion, two hundred forty-two million, four hundred thirty thousand, forty-two".
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