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13401243205134 = 2313335471674887
BaseRepresentation
bin1100001100000011100001…
…0101110011111000001110
31202110010221200101021002220
43003000320111303320032
53224031221230031014
644300240211000210
72552131204515231
oct303007025637016
952403850337086
1013401243205134
1142a7487468554
121605301299066
13762968a375a5
143448a3363418
151838e52a26a9
hexc3038573e0e

13401243205134 has 16 divisors (see below), whose sum is σ = 26802522511488. Its totient is φ = 4467075051512.

The previous prime is 13401243205123. The next prime is 13401243205183. The reversal of 13401243205134 is 43150234210431.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13401243205095 and 13401243205104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7163839 + ... + 8838725.

It is an arithmetic number, because the mean of its divisors is an integer number (1675157656968).

Almost surely, 213401243205134 is an apocalyptic number.

13401243205134 is an abundant number, since it is smaller than the sum of its proper divisors (13401279306354).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13401243205134 is a wasteful number, since it uses less digits than its factorization.

13401243205134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3008439.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 13401243205134 its reverse (43150234210431), we get a palindrome (56551477415565).

The spelling of 13401243205134 in words is "thirteen trillion, four hundred one billion, two hundred forty-three million, two hundred five thousand, one hundred thirty-four".

Divisors: 1 2 3 6 1333547 1674887 2667094 3349774 4000641 5024661 8001282 10049322 2233540534189 4467081068378 6700621602567 13401243205134