Base | Representation |
---|---|
bin | 1100001100000011100001… |
… | …0101110011111000001110 |
3 | 1202110010221200101021002220 |
4 | 3003000320111303320032 |
5 | 3224031221230031014 |
6 | 44300240211000210 |
7 | 2552131204515231 |
oct | 303007025637016 |
9 | 52403850337086 |
10 | 13401243205134 |
11 | 42a7487468554 |
12 | 1605301299066 |
13 | 762968a375a5 |
14 | 3448a3363418 |
15 | 1838e52a26a9 |
hex | c3038573e0e |
13401243205134 has 16 divisors (see below), whose sum is σ = 26802522511488. Its totient is φ = 4467075051512.
The previous prime is 13401243205123. The next prime is 13401243205183. The reversal of 13401243205134 is 43150234210431.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13401243205095 and 13401243205104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7163839 + ... + 8838725.
It is an arithmetic number, because the mean of its divisors is an integer number (1675157656968).
Almost surely, 213401243205134 is an apocalyptic number.
13401243205134 is an abundant number, since it is smaller than the sum of its proper divisors (13401279306354).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13401243205134 is a wasteful number, since it uses less digits than its factorization.
13401243205134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3008439.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 13401243205134 its reverse (43150234210431), we get a palindrome (56551477415565).
The spelling of 13401243205134 in words is "thirteen trillion, four hundred one billion, two hundred forty-three million, two hundred five thousand, one hundred thirty-four".
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