134012497 has 2 divisors, whose sum is σ = 134012498. Its totient is φ = 134012496.

The previous prime is 134012449. The next prime is 134012507. The reversal of 134012497 is 794210431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124746561 + 9265936 = 11169^2 + 3044^2 .

It is a cyclic number.

It is not a de Polignac number, because 134012497 - 2¹⁹ = 133488209 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (134012407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006248 + 67006249.

It is an arithmetic number, because the mean of its divisors is an integer number (67006249).

Almost surely, 2^134012497 is an apocalyptic number.

It is an amenable number.

134012497 is a deficient number, since it is larger than the sum of its proper divisors (1).

134012497 is an equidigital number, since it uses as much as digits as its factorization.

134012497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

The square root of 134012497 is about 11576.3766783912. The cubic root of 134012497 is about 511.7389021625.

The spelling of 134012497 in words is "one hundred thirty-four million, twelve thousand, four hundred ninety-seven".