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13401251103 = 329413757009
BaseRepresentation
bin11000111101100011…
…01101110100011111
31021120221211002111110
430132301231310133
5204421210013403
610053443153103
7653044516632
oct143661556437
937527732443
1013401251103
115757725339
122720075793
1313575608a6
14911b77c19
155367b1103
hex31ec6dd1f

13401251103 has 16 divisors (see below), whose sum is σ = 18935330400. Its totient is φ = 8415697920.

The previous prime is 13401251069. The next prime is 13401251107. The reversal of 13401251103 is 30115210431.

It is not a de Polignac number, because 13401251103 - 230 = 12327509279 is a prime.

It is a super-2 number, since 2×134012511032 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13401251103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401251107) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1874938 + ... + 1882071.

It is an arithmetic number, because the mean of its divisors is an integer number (1183458150).

Almost surely, 213401251103 is an apocalyptic number.

13401251103 is a deficient number, since it is larger than the sum of its proper divisors (5534079297).

13401251103 is a wasteful number, since it uses less digits than its factorization.

13401251103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3757082.

The product of its (nonzero) digits is 360, while the sum is 21.

Adding to 13401251103 its reverse (30115210431), we get a palindrome (43516461534).

The spelling of 13401251103 in words is "thirteen billion, four hundred one million, two hundred fifty-one thousand, one hundred three".

Divisors: 1 3 29 41 87 123 1189 3567 3757009 11271027 108953261 154037369 326859783 462112107 4467083701 13401251103