Base | Representation |
---|---|
bin | 110011000111… |
… | …110011011011 |
3 | 221012212010201 |
4 | 303013303123 |
5 | 11412320212 |
6 | 1155123031 |
7 | 221623603 |
oct | 63076333 |
9 | 27185121 |
10 | 13401307 |
11 | 7623667 |
12 | 45a3477 |
13 | 2a12a8a |
14 | 1acbc03 |
15 | 129ab57 |
hex | cc7cdb |
13401307 has 2 divisors, whose sum is σ = 13401308. Its totient is φ = 13401306.
The previous prime is 13401299. The next prime is 13401313. The reversal of 13401307 is 70310431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13401307 - 23 = 13401299 is a prime.
It is not a weakly prime, because it can be changed into another prime (13401317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700653 + 6700654.
It is an arithmetic number, because the mean of its divisors is an integer number (6700654).
Almost surely, 213401307 is an apocalyptic number.
13401307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401307 is an equidigital number, since it uses as much as digits as its factorization.
13401307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 19.
The square root of 13401307 is about 3660.7795617874. The cubic root of 13401307 is about 237.5284959345.
Adding to 13401307 its reverse (70310431), we get a palindrome (83711738).
The spelling of 13401307 in words is "thirteen million, four hundred one thousand, three hundred seven".
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